Question

Find the greatest number of 4-digits exactly divisible by 12,16,28 and 36​

Answer 1

Answer:

The number that I came up with was 9,072. I found the LCM (Least Common Multiple) using Prime factorization which was 1,008 but you wanted the highest 4 digit number so I multiplied 1,008 to the highest whole number that would still render a 4 digit answer, which was 9 (1,008 * 9 = 9,072).

12 = 2 x 2 x 3

16 = 2 x 2 x 2 x 2

24= 2 x 2 x 2 x 3

28 = 2 x 2 x 7

36 = 2 x 2 x 3 x 3

LCM = 2 x 2 x 2 x 2 x 3 x 3 x 7 = 1,008

1,008 x 9 = 9,072

9,072 is divisible by 12(756), 16 (567), 24 (378), 28 (324), & 36(252)

hp u understand my anser� �right

Answer 2

Answer:

ஃ 9072 is the greatest number of 4-digits exactly divisible by 12, 16, 28 and 36.

Step-by-step explanation:

Step - 1 :- Find the LCM of given numbers

2 | 12, 16, 28, 36

2 | 6, 8, 14, 18

2 | 3, 4, 7, 9

2 | 3, 2, 7, 9

3 | 3, 1, 7, 9

3 | 1, 1, 7, 3

7 | 1, 1, 7, 1

1, 1, 1, 1

LCM of 12, 16, 28 and 36 = 2 × 2 × 2 × 2 × 3 × 3 × 7 = 1008

Step - 2 :- Find the greatest number of 4-digits exactly divisible by given digits by finding the table of 1008

1008 × 1 = 1008

1008 × 2 = 2016

1008 × 3 = 3024

1008 × 4 = 4032

1008 × 5 = 5040

1008 × 6 = 6048

1008 × 7 = 7056

1008 × 8 = 8064

1008 × 9 = 9072

1008 × 10 = 10080