Find the greatest number of 4-digits which is exactly divisible by 40, 48 and 60.
Answers
Answered by
1
Answer:
Happy Father's day
Step-by-step explanation:
The answer is 9840. Hence 9840 is the largest four digit number which is exactly divisible by 40, 48 and 60.
Answered by
5
Answer:
40 = 2 x 2 x 2 x 5
48 = 2 x 2 x 2 x 2 x 3
60 = 2 x 2 x 3 x 5
All three can be factored using 2, 3, and 5. First take the 2. Look for the most times the 2 is multiplied by itself, which is 2 x 2 x 2 x 2
The 3 is used just once and so it the 5, therefore the LCM is 2 x 2 x 2 x 2 x 3 x 5 = 240.
Divide 240 into 9,999, the largest who four-digit number to find that the result is 41 with a remainder of 160. Therefore the largest four-digit number that can be divided by 40, 48, and 60 evenly is 240 x 41 = 9840.
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