find the greatest number of 4 digits which on dividing by 6,18,20,24 and 30 leaves 3 ,15, 17,21 and 27 respectively
Answers
Answer:
9717
Step-by-step explanation:
lets take lcm for 6,18,20,24,30 is 360
leaving remainder
6 - 3 = 3
18 - 15 = 3
20 - 17 = 3
24 - 21 = 3
30 - 27 = 3
mow the greatest four digit no is 9999
on dividing 9999 by lcm value 360
9999 / 360 = 279
Subtract remainder from 9999 we get largest 4 digit number, which is divisible by given number
9999 - 279 = 9720 (9999 but required number gives difference on dividing)
So, our required number = 9720-3 = 9717
Answer:
9717
Step-by-step explanation:
ets take lcm for 6,18,20,24,30 is 360
leaving remainder
6 - 3 = 3
18 - 15 = 3
20 - 17 = 3
24 - 21 = 3
30 - 27 = 3
mow the greatest four digit no is 9999
on dividing 9999 by lcm value 360
9999 / 360 = 279
Subtract remainder from 9999 we get largest 4 digit number, which is divisible by given number
9999 - 279 = 9720 (9999 but required number gives difference on dividing)
So, our required number = 9720-3 = 9717