Question

find the greatest number of 4 digits which when divided by 10 11 15 and 22 leaves remainder 348 and 15 respectively​

Answer 1

Answer:

a) 9907

b)9903

c)9893

d)None

correct answer: c)

Step-by-step explanation:

Largest 4 digit no. is 9999. We see that,each (divisor - remainder) = 7. (10-3)=7,(11-4)=7,(15-8)=7,(22-15)=7. Now take lcm of 10,11,15,22..which is 330. So, lcm + common difference i.e., 330+7= 337. now by dividing 9999 by 337 we get remainder as 106, on subtracting 106 from 9999 we get 9893 which is the required largest four digit no.. Hence, option C is correct.LCM(10,11,15,22)=330

GREATEST 4 DIGIT NO=9999

DIVISIBLE BY 330 WILL BE 9900

HERE 10-3=7,11-4=7,15-8=7,22-15=7

THUS 9900-7=98935 years agoHelpfull: Yes(1) No(0) take lcm of 10,11,15,and 22

which comes out to be 330

and 4 digit maximun number using this lcm is 9900 which is divided by all these i.e 10,11,15,and 22

n now we have to just check out the desired option

n only option c gives us the right answer.

5 years agoHelpfull: Yes(0) No(1) >At first ... take a LCM of (10,11,15,22) = 330

>Now as we know largest 4 digit number is (9999)

>so divide (9999/330) = 30 #reminder we got is 99

> now minus 99 from 9999= 9900 ( here we got highest 4 digit multiple of 330)

#2 step > take a difference of divisor - reminder as follow :-

10-3= 7

11-4= 7

15-8= 7

22-15= 7

as we see above 7 is common difference

#3 step > now minus 7 from 9900 = {9893 } is your answer.

# ( C) 9893