Find the greatest number of 4 digits, which when divided by 24, 32, 40, 48
leaves 3 as remainder.(answer is 9603)
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Correct option is B)
L.C.Mof6,9,12,17=612
Largest 4 digit number which is divisible by 612 is 9792
Now adding reminder 1 will get Largest 4 digit number will be 9792+1 = 9793
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Answer:
9603 is the right answer
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