find the greatest number of 4digits which is exactly divisible by each of 12 ,18,40 and 45 .
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The greatest 4 digit number is 9999. Now, we have to subtract the remainder, which is 279, from 9999.
So, 9720 is the required greatest 4 digit number which is exactly divisible by 12, 18, 40 and 45.
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