Math, asked by vinaygadhiya1122, 10 months ago

Find the greatest number of 5 digit exactly divisible by 12,15,and 36

Answers

Answered by gnagamokshi
7

Answer:

First we will find the LCM of 12,15 and 36

By prime Factorisation,

12=2*2*3

15=5*3

36=2*2*3*3

Now, LCM= 22*32*5

We will find that the LCM is 180

Now, Largest 5 digit number= 99999

Dividing this number by LCM, we get,

99999/180=555.5

Now we will multiply 180 by 555

We will get 99900

We will check now and observe,

99900/12=8325

99900/15=6660

99900/36=2775

Hence 99900 is the greatest 5 digit number divisible by 12,15 and 36.

Step-by-step explanation:

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Answered by nitinsengar3
1
First take the L.C.M of 12, 15 and 36 = 180
Greatest five 5 digit number =99999.

Now dividing 99999 by 180 we get 555 as the quotient and 99 as the remainder.
Now, subtracting this remainder from 99999, we get
99999 - 99 = 99900.

largest number which is divisible by 12, 15 and 36= 99900

To check whether 99900 is exactly divisible by 12, 15 and 36:
99900/12 = 8325
99900/15 = 6660
99900/36 = 2775
So we can see 99900 is exactly divisible 12, 15 and 36.

Answer greatest number is 99900.

Hopefully it’s helpful for you
Thanks
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