Find the greatest number of 5 digit exactly divisible by 12,15,and 36
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Answered by
7
Answer:
First we will find the LCM of 12,15 and 36
By prime Factorisation,
12=2*2*3
15=5*3
36=2*2*3*3
Now, LCM= 22*32*5
We will find that the LCM is 180
Now, Largest 5 digit number= 99999
Dividing this number by LCM, we get,
99999/180=555.5
Now we will multiply 180 by 555
We will get 99900
We will check now and observe,
99900/12=8325
99900/15=6660
99900/36=2775
Hence 99900 is the greatest 5 digit number divisible by 12,15 and 36.
Step-by-step explanation:
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Answered by
1
First take the L.C.M of 12, 15 and 36 = 180
Greatest five 5 digit number =99999.
Now dividing 99999 by 180 we get 555 as the quotient and 99 as the remainder.
Now, subtracting this remainder from 99999, we get
99999 - 99 = 99900.
largest number which is divisible by 12, 15 and 36= 99900
To check whether 99900 is exactly divisible by 12, 15 and 36:
99900/12 = 8325
99900/15 = 6660
99900/36 = 2775
So we can see 99900 is exactly divisible 12, 15 and 36.
Answer greatest number is 99900.
Hopefully it’s helpful for you
Thanks
Greatest five 5 digit number =99999.
Now dividing 99999 by 180 we get 555 as the quotient and 99 as the remainder.
Now, subtracting this remainder from 99999, we get
99999 - 99 = 99900.
largest number which is divisible by 12, 15 and 36= 99900
To check whether 99900 is exactly divisible by 12, 15 and 36:
99900/12 = 8325
99900/15 = 6660
99900/36 = 2775
So we can see 99900 is exactly divisible 12, 15 and 36.
Answer greatest number is 99900.
Hopefully it’s helpful for you
Thanks
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