Math, asked by ananyasen889, 10 months ago

Find the greatest number of 5 digits exactly divisible by
12, 16, 18 and 21.​

Answers

Answered by suhani102444
5

Answer:

The greatest 5 digit no. divisible by 12,16,18 and 21 is 99720

Hope it's helps you

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Answered by niishaa
15

Answer:

the greatest number of 5 digits exactly divisible by 12, 16, 18 and 21. = 99792

Step-by-step explanation:

To find : The Greatest 5 digit number exactly divisible by 12,16,18 and 21?

Solution :  

The greatest 5-digit number is 99999.

Now, Find the LCM of 12,16,18 and 21.

2 |  12  16  18  21

2 |   6  8   9   21

2 |  3   4   9   21

2 | 3   2   9   21

3 |  3   1    9   21

3 |   1   1    3   7

7  |  1   1   1   7

| 1 1 1 1

LCM (12,16,18,21) = 2×2×2×2×3×3×7

LCM(12,16,18,21) = 1008

Divide 99999 by 1008 so that we get the remainder,

99999 = 99×1008+207

Remainder is 207.

Now, Subtract the remainder from 99999.

99999–207 = 99792

Therefore, The required number is 99792 which is exactly divisible by 12,16,18 and 21.

Hope this will help you :)

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