find the greatest number of 5 digits exactly divisible by 12, 15 and 36
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10080 is the smallest number
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First we will.find the L.C.M of 12,15 and 36
12 = 2×2×3
15 =5×3
36 = 2×2×3×3
L.C.M = 22 × 32 × 5
L.C.M = 180
Now the largest 5 digit no. is 99999
Dividing the no. by L.C.M
99999/180 = 555.5
On multiplying 180 × 555
We will get 99900
We will check now and verify :
99900/12 = 8325
99900/15 =6660
99900/36 = 2775
Since it is divisible by all of them.
Therefore 99900 is the largest 5 digit no. which is divisible by 12,15 and 36.
Hope it helps.
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