Question

find the greatest number of 5 digits,that will give you remainder of 5 when divided by 8 and 9 respectively?

Answer 1

lcm of (8,9)=72
the greatest no. of 5 digit is 99999
now, (99999÷72) then we get 63 reminder , 1st we hv to sub the reminder in 99999 nd add 5
so resultant no. is = 99999-63+5=99941

Answer 2

Answer:

The greatest number of 5 digits,that give remainder of 5 when divided by 8 and 9 respectively is  99941.

Step-by-step explanation:

Given numbers are 8 and 9.

To find: Greatest 5-digit number which leaves 5 as remainder when divided by given numbers.

Greatest 5-Digit number = 99999

LCM of 8 and 9,

8 = 2 × 2 × 2

9 = 3 × 3

LCM = 2 × 2 × 2 × 3 × 3 = 72

Now we find Greatest 5-digit number divisible by 8 and 9 by dividing 99999 by 72.

On division we get, (attached in pic)

Quotient = 1388

Remainder = 63

So, the greatest 5-digit number divisible by 8 and 9 = 99999 - 63 = 99936

Required number = 99936 + 5 = 99941

Therefore, The greatest number of 5 digits,that give remainder of 5 when divided by 8 and 9 respectively is 99941.