Question

Find the greatest number of 5-digits which on being funded by 9 12 24 and 39 as remainders respectively

Answer 1

Answer:

99714

Step-by-step explanation:

The difference between the divisor and the remainder is same in all the cases which is 6

STEP 1:

LCM OF DIVISORS

LCM OF(9,12,24,45) IS 360

STEP 2:

We know the largest five digit number is 99999

Now to find the largest five digit number which satisfy the given conditons then do the following

A) 360*N-6

N, is the quotient of 99999/360

U will get the answer as 360*277-6= 97214

B) Divide 99999/360

U will get remainder as 279

SUBTRACT 279 FROM 99999 WHICH IS 99720

Now 99720-6- 97214 which will be ur answer

OR

3=x mod 9

6=x mod 12

18-x mc 24

39 x mod 45

Modulo values in each case is number-6.

Number is LCM-6

-360-6

=354

To find largest five digit number, 360x-6 where x is integer.

100000/360= 10000/36=277

Largets 5 digit number =360*277-6

-99720-6

-99714

This one was a bit tricky though.

Hope it was simple illustration.

Good luck and don't forg to upvote if you liked how it was solved.