Question

find the greatest number of 5 digits which when divided by 3; 5; 8 and 12 will leave 2 as remainder.​

Answer 1

9999999999999999999999999

Answer 2

Answer:99962

Step-by-step explanation:

Find the LCM of the given numbers

Find the integral multiple LCM to give you the largest possible 5 digit number

Add 2 to it (If you happen to go into 6 digit number then subtract the LCM from the 6 digit number)

LCM of 3, 5, 8 and 12 is 120.

120*833 = 99,960 (120*834 = 1,00,020, which is of no use)

2 added to 99,960 is 99,962 (still a five digit number!).

The required answer is 99,962