find the greatest number of 5 digits which when divided by 3; 5; 8 and 12 will leave 2 as remainder.
Answers
Answered by
1
9999999999999999999999999
Answered by
1
Answer:99962
Step-by-step explanation:
Find the LCM of the given numbers
Find the integral multiple LCM to give you the largest possible 5 digit number
Add 2 to it (If you happen to go into 6 digit number then subtract the LCM from the 6 digit number)
LCM of 3, 5, 8 and 12 is 120.
120*833 = 99,960 (120*834 = 1,00,020, which is of no use)
2 added to 99,960 is 99,962 (still a five digit number!).
The required answer is 99,962
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