Question

find the greatest number of 5-digits which when divided by 25,30 and 40 leaves a reminder of 20,25 and 35 respectively

Answer 1

Answer:

So the smallest five- digit number divisible by 25, 30 and 40 is (600 x 17)=10200. Therefore the required number is= (10200–5)= 10195. This number will give a remainder of 20, 25 and 35 when divided by 25, 30 and 40 Respectively

Step-by-step explanation:

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