Question

Find the greatest number of 6 digit which is a perfect square..




Step by step explanation....​

Answer 1

Step-by-step explanation:

greatest 6 digit number=999999

square root of 999999 =999.9995 (approximately)

1000^2= 1000000(seven digits)

999^2=998001

therefore 998001 is the greatest number.

Answer 2

HeRe Is Your Ans ⤵

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➡Let X² be the largest six-digit perfect square

The largest six-digit number is 999999 So

X² ≤ 999999

We know that 1000² = 1000000

which is only 1 more than 999999 So X² must be the next smaller square, which is (1000 - 1)²

(1000 - 1)² = 999² = 998001

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