find the greatest number of 6 digit which is a perfect square find the square root of this number by the method of long division
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beautifulkiss
beautifulkiss Helping Hand
Let x² be the largest six-digit perfect square.
The largest six-digit number is 999,999, so
x² ≤ 999,999.
You know that 1,000² = 1,000,000, which is only 1 more than 999,999, so x² must be the next smaller square, which is (1,000 - 1)².
(1,000 - 1)² = 999² = 998,001
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the greatest 6digit no. is 999999.
take square root of 999999.
then the remainder is 1998.
then subtract from 999999 to 1998.
the answer is 998001.
it is the perfect square of the number 999.
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