Question

find the greatest number of 6 digit which is exactly divisible by 24,15 and 36.
please answer quickly​

Answer 1

Answer:

The greatest number of  6 digits  =  999999

First, we need to find the LCM of 24, 15 and 36 and then divide 6 digits number 999999 by the LCM and subtract the remainder  from 6 digit number 999999.

24, 15 and 36

24 = 2 x 2 x2 x3

15 = 3 x 5

36 = 2 x 2 x 3 x 3

L.C.M of 24, 15 and 36 = 360

Now, 999999 /  360

quotient =  2777

Remainder =  279

Therefore, the remainder is 279. Hence the required number is = 999999 – 279 = 999720

Hence, 999720 is the greatest number of 6 digits exactly divisible by 24, 15 and 36.

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Step-by-step explanation:

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Answer 2

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SOLUTION:

The greatest number of 6 digits = 999999

First, we need to find the LCM of 24, 15

and 36 and then divide 6 digits number

999999 by the LCM and subtract the remainder from 6 digit number 999999.

24, 15 and 36

24 = 2x 2 x2 x3

15 = 3x 5

36 = 2x 2x3x3

L.C.M of 24, 15 and 36 ° 360

Now, 999999/ 360

Quotient = 2777

Remainder = 279

Therefore, the remainder is 279. Hence

the required number is 999999 - 279 =

999720>

Hence, 999720 is the greatest numberof 6 digits exactly divisible by 24, 15 and 36.

I hope it helps you...

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