Question

Find the greatest number of 6 digit which is exactly divisible by 27,45,60,72 and 96

Answer 1

Solution:-
LCM of 27,45,60,72 and 96= 4320
Greatest 6 digit number =99999
When we divide 999999 by 4320 we get the remainder==231.48

So,

The largest number will be=4320×231
=997920

Answer 2

Answer:

Required number is 997920

Step-by-step explanation:

Given numbers are 27 , 45 , 60 , 72 and 96

We have to find greatest 6-digit number which is divisible by given numbers.

We first find lowest Common Multiple of given numbers then we find multiple of LCM which greatest 6 digit number.

27 = 3 × 3 × 3

45 = 5 × 3 × 3

60 = 2 × 3 × 2 × 5

72 = 2 × 2 × 2 × 3 × 3

96 = 2 × 2 × 2 × 2 × 2 × 3

LCM = 3 × 3 × 2 × 2 × 2 × 2 × 2 × 3 × 5 = 4320

Now we find the multiples of 4320 which is largest 6 digit number

for divide 999999 ÷ 4320 we get 231.48125

So, 231st multiple of 4320 is largest 6 digit number .i.e., 4320 × 231 = 997920

Therefore, required number is 997920