Find the greatest number of 6 digits e4xactly divisioble n=by 18,24 and 36
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LCM (18,24,36) = 72
divide 6 digit largest number i.e 999999 by 72
which will give 63 as remainder .
now subtract 63 from 999999
i.e 999999-63 = 999936
since there are no remainder of divisor 18,24and 36
therefore the required number is 999936.
divide 6 digit largest number i.e 999999 by 72
which will give 63 as remainder .
now subtract 63 from 999999
i.e 999999-63 = 999936
since there are no remainder of divisor 18,24and 36
therefore the required number is 999936.
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