Question

find the greatest number of 6 digits exactly divisible by 24 15 and 36 ​

Answer 1

Answer :

The greatest number of 6 digits is 999720 .

Step-by-step explanation :

We can solve this question by taking LCM of 24, 15 and 36 , respectively.

Then we'll divide 6 digits no. 999999 [Greatest 6 digit number ]by the resultant LCM and subtract the remainder from 6 digit no. 999999.

Finding the LCM,

LCM = 24, 15 and 36

• 24 = 2 × 2 × 2 × 3

• 15 = 3 × 5

• 36 = 2 × 2 × 3 × 3

L.C.M of 24, 15 and 36 :

➟2 × 2 × 2 × 5 ×3 × 3

➟360

Now, we'll divide 6 digits no. 999999 by the resultant LCM and subtract the remainder from 6 digit no. 999999.

➟999999 /360

❏ Q = 2777 [Quotient ]

❏ R = 279 [ Remainder ]

Required number :

➟999999 - 279

➟999720

Therefore, 999720 is the required greatest number.

Answer 2

Answer:

SOLUTION :  

The greatest number of  6 digits  =  999999

First, we need to find the LCM of 24, 15 and 36 and then divide 6 digits number 999999 by the LCM and subtract the remainder  from 6 digit number 999999.

24, 15 and 36

24 = 2 x 2 x2 x3

15 = 3 x 5

36 = 2 x 2 x 3 x 3

L.C.M of 24, 15 and 36 = 360

Now, 999999 /  360

quotient =  2777

Remainder =  279

Therefore, the remainder is 279. Hence the required number is = 999999 – 279 = 999720

Hence, 999720 is the greatest number of 6 digits exactly divisible by 24, 15 and 36.

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