Find the greatest number of 6 digits exactly divisible by 24, 15 and 36
Answers
Answered by
14
find out the LCM of 24,15 and 36
LCM=360
Now,
We will divide this number by LCM of 24,15 and 36,
we will get,
999999/360=279
now sutract LCM and the no.
answer comes out to be
999720
so,
999720 is the greatest number 6-digit number divisible by 24,15 and 36.
PLS MARK IT THE BRAINLIEST ANSWER
if it could help u out
LCM=360
Now,
We will divide this number by LCM of 24,15 and 36,
we will get,
999999/360=279
now sutract LCM and the no.
answer comes out to be
999720
so,
999720 is the greatest number 6-digit number divisible by 24,15 and 36.
PLS MARK IT THE BRAINLIEST ANSWER
if it could help u out
Answered by
3
LCM(24,15,36)
24=2^3*3
15=3*5
36=2^2 * 3^2
LCM= 2^3* 3^2 * 5 =360.[Any number which is a multiple of 360 will be divisible by 24,15 and 36]
Greatest 6 digit number = 9,99,999. when 999999 is divided by 360, it leaves a remainder 279. Hence required number is 9,99,999 - 279= 9,99,720 greatest 6 digit number which is exactly divisible by 24,15 and 36.
Ans) 9,99,720
24=2^3*3
15=3*5
36=2^2 * 3^2
LCM= 2^3* 3^2 * 5 =360.[Any number which is a multiple of 360 will be divisible by 24,15 and 36]
Greatest 6 digit number = 9,99,999. when 999999 is divided by 360, it leaves a remainder 279. Hence required number is 9,99,999 - 279= 9,99,720 greatest 6 digit number which is exactly divisible by 24,15 and 36.
Ans) 9,99,720
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