find the greatest number of 6 digits which is a perfect square. (with rough work) please
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Answer:
998001
Let the largest number be 999999 and then find the root of this number, You will get remainder as 1998, subtract it from that number.
Answered by
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Answer :998001
Step-by-step explanation:
The largest 6 digit which is a perfect square is 998001=(999)^2
The largest 6 digit number is 999999.While it is not a perfect square, when 1 is added to it we get 1000000 which is smallest seven digit number and also perfect square =(1000)^2
So the smallest 6 digit number which is perfect square =(1000–1)^2=(999)^2=998001
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