Question

find the greatest number of 6 digits which is a perfect square. (with rough work) please​

Answer 1

Answer:

998001

Let the largest number be 999999 and then find the root of this number, You will get remainder as 1998, subtract it from that number.

Answer 2

Answer :998001

Step-by-step explanation:

The largest 6 digit which is a perfect square is 998001=(999)^2

The largest 6 digit number is 999999.While it is not a perfect square, when 1 is added to it we get 1000000 which is smallest seven digit number and also perfect square =(1000)^2

So the smallest 6 digit number which is perfect square =(1000–1)^2=(999)^2=998001