Find the greatest number of 6 digits, which is a perfect square.
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Answered by
31
The largest six-digit number is 999,999, so
x² ≤ 999,999.
You know that 1,000² = 1,000,000, which is only 1 more than 999,999, so x² must be the next smaller square, which is (1,000 - 1)².
(1,000 - 1)² = 999² = 998,001.
The largest six-digit perfect square is 998,001.
x² ≤ 999,999.
You know that 1,000² = 1,000,000, which is only 1 more than 999,999, so x² must be the next smaller square, which is (1,000 - 1)².
(1,000 - 1)² = 999² = 998,001.
The largest six-digit perfect square is 998,001.
Answered by
7
x² = 998,001 is the answer....
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