Question

Find the greatest number of 7 digit which is exactly divisible by 12,15 and 21.​

Answer 1

Step-by-step explanation:

Find the LCM of 12, 15 and 21. Multiply the LCM by a positive integer so large that you get the

largest 7 digit number. (The LCM is 420 and you multiply with 23809 to get 9999780 the largest 7 digit ...

plss do mark my answer as brilliant

thank u

Answer 2

$\huge {\mathcal{\purple{H}\green{e}\pink{y}\blue{!}}}$

For this, Find LCM of 12, 15 and 21

i.e. 420.

Now, since we want a 7 digit number, so, we must Multiply 420 with some number such that it becomes 7 digit..

To find by which number to Multiply, Divide 420 by largest 7 digit number, i.e. 9999999.

So, 9999999÷420 = 23809.5214

So let's try multiplying 23809 with 420,

23809×420 = 9,999,780 Answer!

$<marquee><font color= "red">$Hope it helps you mark as brainliest please