find the greatest number of children to whom 135 banana 225 mangoes and 315 pears can be divided eqally
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Answered by
1
For a number of boxes to be the least, the number of fruits in each box should be maximum.
As per the given data, the number of fruits in each box is equal to the HCF of 96 and 112, i.e., 16.
Therefore, minimum number of boxes =
16
96
+
16
112
=13.
Answered by
1
Step-by-step explanation:
● HCF (135, 225, 315) = 45
Hence, the greatest number of children to whom 135 banana 225 mangoes and 315 pears can be divided equally is 45.
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