Question

find the greatest number of Five digit which is divisible by 287

Answer 1

Consider the smallest 6 digit number. 100000.

We know that 100000 is divisible by 25.

[100000=1000*100=1000(4*25)=25(4000)]

In order to get the biggest 5 digit number, subtract 25 from the smallest 6 digit number.

That is, 100000–25 = 99975

[100000 – 25 = 25(4000) - 25

= 25(4000–1) = 25(3999)]

So, 99975 is the answer.

Answer 2

Greatest 5-digit number = 99999

Find the quotient when 99999 is divided by 287:

99999 ÷ 287 = 348 remainder 123

⇒ the quotient is 348

Find the greatest 5-digit numbers that can be divisible by 287:

Greatest 5-digit number = 348 x 287 = 99875

Answer: The greatest 5-digit number that can be divided by 287 is 99875