Question

Find the greatest number of five digits which on dividing by 3 12 18 24 30 36 leaves remainder 2 11 17 23 29 35 respectively? ​

Answer 1

Answer:

The required number is 99719.

Step-by-step explanation:

Consider the  provided numbers.

The greatest 5 digit number is 99999.

Now we will find the LCM of 3, 12, 18, 24, 30, 36.

3 = 1 × 3

12 = 2 × 2 × 3

18 = 2 × 3 × 3

24 = 2 × 2 × 2 × 3

30 = 2 × 3 × 5

36 = 2 × 2 × 3 × 3

Thus, the LCM is: 2 × 2 × 2 × 3 × 3 × 5 = 360.

Divide 99999 by 360.

$99999 = 277 \times 360 + 279$

Remainder is 279.

Now, subtract 279 from 99999 we get,

99999 - 279 = 99720

Now calculate the difference of divider and remainder is:

3 - 2 = 1, 12 - 11 = 1, 18 - 17 = 1 ..... Therefore the common difference is 1.

So subtract the number 1 with the 99720.

Which gives 99720 - 1 = 99719.

Hence, the required number is 99719.

Answer 2

Answer:

what is smallest ten digit number