Question

find the greatest number of five digits which when divided by 3,5,8,12 leaves 2 as remainder?
pls help send with explanation fds​

Answer 1

Step-by-step explanation:

LCM of (3, 5, 8, 12)

⇒ 3 × 5 × 4 × 2 = 120

⇒ Now greatest five digits number is 99999

On dividing 99999 by = 120 (LCM)

We get remainder = 99999120,

remainder = 39

⇒ By subtracting remainder from 99999 we get the greatest five digits number which is completely divisible by given numbers (3, 5, 8, 12)

∴ 99999 - 39 = 99960

⇒ Now, we required greatest five digit number which when divided by (3, 5, 8, 12) leaves remainder 2 in each case.

⇒ add 2 in the 99960

⇒ 99960 + 2

⇒ 99962