Question

Find the greatest number of five digits which when divided by 3, 5, 8, 12 has 2 as remainder

1 point​

Answer 1

Answer:

LCM of 3, 5, 8 and 12 is 120.

120*833 = 99,960 (120*834 = 1,00,020, which is of no use)

2 added to 99,960 is 99,962 (still a five digit number!).

The required answer is 99,962.

Answer 2

Answer:

99962

Step-by-step explanation:

• LCM of 3 , 5 , 8 and 12

= 2×3×4×5 = 120

• Now, greatest five digits number is 99999 On dividing 99999 by 120 (LCM)

We get remainder = 99999/120 , remainder is 39

• By subtracting remainder from 99999 we get the greatest five digits number which is completely divisible by given numbers (3,5,8,12)
• 99999-39 = 99960
• Now, we required greatest five digit number which when divided by 3,5,8, 12 leaves remainder 2 in each case
• Add 2 in the 99960
• 99960 + 2
• 99962
• Hence, 99962 is the correct answer

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