Find the greatest number of five digits which when divided by 16, 24, 30 & 36 will leave a remainder 10 in each case. Please friends answer it with further explanation...
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Answered by
1
Answer:
Largest number of 5 digits =99999. Lcm 0f 16,24,30 and 36=720 On dividing remainder obtained is 639. Largest number of 5 digits divisible by 16,24,30 and 36 =(99999-639)=99360 Hence required number is (99360+10)=99370
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Answered by
4
Answer:
16=2×2×2×2
24=2×2×2×3.
30=2×3×5.
36=2×2×3×3.
L.C.M.=2×2×2×2×3×3×5=720 (3 digits number)
Largest number of 5 digits =99999
99999÷720=138.8875.
Thus , possible largest 5 digits number=720×138= 99360
Required largest 5 digits number= 99360+10=99370. Answer
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