Question

Find the greatest number of five digits which when Divided by 4,6, 10 , and 15 leaves the same remainder 3 in each case ?
A/ 99993 B/ 99063
C/ 90093 D/ 99963 ​

Answer 1

Answer

L.C.M. of 4, 6, 10 and 15 = 60 Least number of six digits = 100000

Dividing 100000 by 60 we get remainder = 40

∴ Least number of six digits divisible by 4, 6, 10 and 15

= 100000 + (60 - 40) = 100020

∴ N = 100020 + 2 = 100022

∴ Sum of digits in N = 1 + 0 + 0 + 0 + 2 + 2 = 5