Question

find the greatest number of five digits, which when divided by 11, 21, 15, 28 leaves 5, 15, 9 and 22 as remainders respectively.​

Answer 1

Answer:

When 99999 is divided by 360, leaves the remainder 279

So,

99999−279=99720

Now here, we can see that

3−2=1,

12−11=1,

18−17=1,

24−23=1,

30−29=1,

36−35=1

The difference of divisors and their corresponding remainders is 1.

So, the required five digit number will be 1 less than $99720$$.

The required number is 99720−1=99719

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