find the greatest number of four digit which on dividing 8 16 24 36 leaves remainder 4 in each case
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Let x be the unknown number.
Then x-10 is divisible by 16, 24, 30 and 36, according to the condition.
It implies that x-10 is divisible by , and .
Hence, x-10 is divisible by 16*5*9 = 720.
The greatest 5-digits number divided by 720 is 99360 (it is easy to check).
It means that x-10 = 99360.
Hence, x = 99370
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