Math, asked by MeenaHandique, 10 months ago

Find the greatest number of four digits and the least number of five digits which when divided by 789 leaves remainder 5 in each case.

Answers

Answered by sahanaj6241
5

greatest 4 digits number =9999

smallest 5 digits number =10000

9999÷789= Q=12. R=531

9999-531=9468

9468+5=9473

therefore, the greatest 4 digits number when divided by 789 gives 5 as remainder =9473

10000÷789= Q=12 R=532

789-532=257

257+5=262

10000+262=10262

therefore, the smallest number of five digits which when divided by 789 gives remainder 5 = 10262


MeenaHandique: Thanks, it helped me a lot.
sahanaj6241: welcome
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