Math, asked by karthickraja1212, 11 months ago

find the greatest number of four digits exactly divisible by 15, 21, 27.​

Answers

Answered by yuvraj99975
3

9720 is the answer ...

.....

Answered by PcEdu21
2

Answer:

9720

Step-by-step explanation:

LCM of (12, 15, 18, 27)

⇒ 4 × 3 × 5 × 3 × 3 = 540

largest 4-digits number = 9999 on dividing by 540 to number = 

9999÷540

remainder = 279

Required number = 9999 - 279 = 9720

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