find the greatest number of four digits exactly divisible by 15, 21, 27.
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3
9720 is the answer ...
.....
Answered by
2
Answer:
9720
Step-by-step explanation:
LCM of (12, 15, 18, 27)
⇒ 4 × 3 × 5 × 3 × 3 = 540
largest 4-digits number = 9999 on dividing by 540 to number =
9999÷540
remainder = 279
Required number = 9999 - 279 = 9720
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