Math, asked by peter2196, 1 year ago

Find the greatest number of four digits which is exactly divisible by 16,24,28,35

Answers

Answered by MakutoShiedo
87
LCM of 16, 24, 28 and 35 is 1680.
Greatest number of 4- digits is 9999.
(Divide 9999 by 1680)
The remainder is 1599.
Required number= 9999 - 1599
= 8400
Ans.=8400 is the greatest number of 4- digits that is exactly divisible by 16,24,28 and 35.
Answered by Abhijeet1589
0

Greatest 4-digit number exactly divisible by the given divisors is 8400

GIVEN

Divisor = 16,24,28,35

TO FIND

Greatest 4-digit number exactly divisible by the given divisors.

SOLUTION

We can simply solve the above problem as follows;

To calculate the number exactly divisible by 16,24,28,35 we will first calculate the LCM of the given number

2 |16, 24, 28, 35

2 |4, 12, 14, 35

2 |2, 6, 7, 35

2|1, 3, 7, 35

3 |1, 1, 7, 35

7 |1, 1, 1, 5

5 |1, 1, 1, 1

LCM = 2×2×2×2×3×5×7 = 1680

Now, This is the smallest 4-digit number exactly divisible by the given numbers.

We know that the highest 4-digit number is 9999

Number divisible by given numbers = 9999/1680

The remainder is 8400.

Hence, Greatest 4-digit number exactly divisible by the given divisors is 8400

#Spj2

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