Question

Find the greatest number of four digits
which when divided by 10, 11, 15 and 22
leaves 3, 4, 8 and 15 as remainders
respectively ?
​

Answer 1

Step-by-step explanation:

First you have to do subtraction with the numbers like 10-3,11-4,15-8,22-15. After the results which you will get you have to do the Job ..F

Answer 2

Answer:

greatest 4 digit no.is 9999.

now,

10-3=7

11-4=7

15-8=7

22-15=7

now lcm(10,11,15& 22)=330

and common difference (10,11,15 &,22)=7

then,

LCM +common diff.=330+7

=337.

on dividing 9999 by 337 is 106

then ,

required no is 9999 - 106=9893

hope it helps u!!!!