Question

Find the greatest number of sic
digits exactly divisible by 15, 24
and so.​

Answer 1

Answer:The greatest number of  6 digits  =  999999

First, we need to find the LCM of 24, 15 and 36 and then divide 6 digits number 999999 by the LCM and subtract the remainder  from 6 digit number 999999.

24, 15 and 36

24 = 2 x 2 x2 x3

15 = 3 x 5

36 = 2 x 2 x 3 x 3

L.C.M of 24, 15 and 36 = 360

Now, 999999 /  360

quotient =  2777

Remainder =  279

Therefore, the remainder is 279. Hence the required number is = 999999 – 279 = 999720

Hence, 999720 is the greatest number of 6 digits exactly divisible by 24, 15 and 36.

HOPE THIS ANSWER WILL HELP YOU…

Step-by-step explanation: