Find the greatest number of sin digits exactly divisible by 15,24 and 3.
Answers
Answered by
1
Answer:
9
Step-by-step explanation:
9 will be the greatest number I think
Answered by
1
Answer:
Let us find the LCM of 24,15 & 36
LCM of 24 = 2 × 2 × 2 × 3
LCM of 15 = 3 × 5
LCM of 36 = 2 × 2 × 3 × 3
LCM of (24, 15 and 36) = 23 × 32 × 5
LCM of (24, 15 and 36) = 8 × 9 × 5 = 360
The greatest 6-digit number is 999999
Let us divide the greatest 6-digit number by LCM of (24, 15 and 36)
⇒ 999999/360
Reminder is 279
∴ 999999−279 = 999720
999720 is the greatest number 6-digit number divisible by 24,15 and 36
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