Math, asked by bamsharish, 6 hours ago

Find the greatest number of sin digits exactly divisible by 15,24 and 3.​

Answers

Answered by anandsharmagidcvapi
1

Answer:

9

Step-by-step explanation:

9 will be the greatest number I think

Answered by thestickmanlegendspr
1

Answer:

Let us find the LCM of 24,15 & 36

LCM of 24 = 2 × 2 × 2 × 3  

LCM of 15 = 3 × 5

LCM of 36 = 2 × 2 × 3 × 3  

LCM of (24, 15 and 36) = 23 × 32 × 5

LCM of (24, 15 and 36) = 8 × 9 × 5  = 360

The greatest 6-digit number is 999999

Let us divide the greatest 6-digit number by LCM of (24, 15 and 36)

⇒ 999999/360

Reminder is 279

∴ 999999−279 = 999720

999720 is the greatest number 6-digit number divisible by 24,15 and 36

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