Find the greatest number of six digit
exactly divisible by 15, 24 & 30?
Attachments:
Answers
Answered by
4
Answer:
For this you will need to find the lowest common multiple of the three numbers.
Lcm of 15,24,30=120(3*5*2*2*2)
Largest 6 digit number =999999.
Next we divide it by the Lcm.
Dividing it by 120 we get 999999/120=8333.325
Hence the largest number divisible by 120 =8333*120=999960
Hope it helps you keep smiling :)
This is the answer according to your question
Answered by
3
Answer:
I can divide 999,999 by 15, 24, and 30. If you mean what is the greatest 6 digit number that is an integer multiple of 15, 24, and 30, then my response is 999,960.
Similar questions