Question

find the greatest number of six digit which is a perfect square. find the square root of this number​

Answer 1

Step-by-step explanation:

ANSWER

The largest 6 digit which is a perfect square is 998001=(999) ^2

The largest 6 digit number is 999999.While it is not a perfect square, when 1 is added to it we get 1000000 which is smallest seven digit number and also perfect square =(1000) ^2

So the smallest 6 digit number which is perfect square =(1000–1) ^2

=(999) ^2

Answer 2

$\huge \bf{Question}$

➡Find the greatest number of six digit which is a perfect square. find the square root of this number?

$\huge \bf{Answer}$

➡We know the greatest number of 6 digits is 999999.

 Then solving through division method,

We get quotient as 999.99 So it is not a perfect square.But if we consider it to be as (1000-1)² which will be equal to 999².

             

$1000 - 1 {}^{2} = 999 {}^{2} = 998001$

So the perfect square of greatest 6 digit number is 998001.        

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