Question

.Find the greatest number of six digit which is perfect square. Find the square root of this number ​

Answer 1

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The greatest number of six digit is 999999

Now

$\sqrt{999999} = 999.999$

So the required number is

${999}^{2} = 998001$

and square root of the number is

$\sqrt{998001} = 999$

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Answer 2

Answer:

36 is the answer about the question