Find the greatest number of six digits exactly divisible by 18,24 and 36(with steps)
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hye
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we have to find the greatest six digit number exactly divisible by 24,18 and 36
=>first let us find the lcm of 24,18 and 36
=>prime factorisiation of 24 = 2*2*2*3
prime factorisiation of 18= 3*3*2
prime factorisiation of 36= 2*2*3*3
common factors = 2×2×2×3×3×3
=8×27
=216
lcm = 216
greatest 6 digit = 999999
=>now lets divide 999999/216
=>4629.625
=>4629 aprrox
now,
=>4629 *360
=>999864
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hope it helps u........
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