Math, asked by JAYmilind1240, 1 year ago

Find the greatest number of six digits exactly divisible by 18,24 and 36(with steps)

Answers

Answered by Raghav3333
7


hye
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we have to find  the greatest six digit number exactly divisible by 24,18 and 36

=>first let us find the lcm of 24,18 and 36


=>prime factorisiation of 24 =  2*2*2*3

prime factorisiation of 18=  3*3*2


prime factorisiation of 36=   2*2*3*3 

common factors = 2×2×2×3×3×3

=8×27


=216

lcm = 216 

greatest 6 digit = 999999


=>now lets divide 999999/216
=>4629.625


=>4629 aprrox


now,
=>4629 *360

=>999864





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hope it helps u........


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