Find the greatest number of six digits which is a perfect square. Find the square
root of this number
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we have to find the greatest number of 6 digit which is a perfect square find the square root of this number ?
greatest 6 digit number = 999999
=> who have to do long division method for 999999
we get the quitting and 99.99 (long division) it is not a perfect square
=> x^2 < 999,999
So, x is a number whose square is the next least square before 999999
So, let form an equation :-
=> (1000 - 1)^2 = 999^2
=> 999 × 999 = 998001
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