Math, asked by perfectakashakash, 8 months ago

Find the greatest number of six digits which is a perfect square. Find the square
root of this number​

Answers

Answered by ts0610858
0

Answer:

289444 is the greatest six digit number whose square root is 538

Answered by Dead3ill
0

Answer:

998001 ; sq. root = 999

Step-by-step explanation:

let x^2 be the largest 6-digit squre number.

we know that 999999 is the largest 6-digit no.

And, (1000)^2 = 1,000,000 which is 1 more than 999999.

So (1000 - 1)^2 should be less than 999999 ...

=> (999)^2 = 998001

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