Find the greatest number of six digits which is a perfect square. Find the square
root of this number
Answers
Answered by
0
Answer:
289444 is the greatest six digit number whose square root is 538
Answered by
0
Answer:
998001 ; sq. root = 999
Step-by-step explanation:
let x^2 be the largest 6-digit squre number.
we know that 999999 is the largest 6-digit no.
And, (1000)^2 = 1,000,000 which is 1 more than 999999.
So (1000 - 1)^2 should be less than 999999 ...
=> (999)^2 = 998001
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