Question

find the greatest number of six digits which on division by 42,45,48,56 and 60 leaves 12 as remainder in each case.​

Answer 1

Answer:

Find the LCM of the divisors required. 

LCM of 42, 45, 48, 56 and 60 = 5040. 

Find the largest 6 digit multiple of 5040. 

The largest 6 digit number is 999999. 

999999 divided by 5040 gives quotient 198 and remainder 2079. 

So 5040 x 198 = 999999 - 2079 = 997920 is the largest 6 digit multiple of 5040. 

Add the remainder 12 which is required in the question. 

997920 + 12 = 997932. 

∴ 997932 is the answer. 

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