Question

find the greatest number of six digits which one being divided by 6,7,8,9 and 10 leaves 5,6,7 and 8 as remainder respectively ​

Answer 1

Answer:

997920

Step-by-step explanation:

First we need to find the common difference between divisors and remainders

Here it is 2

6-4= 2

7-5=2

10-8=2

And the common number of all divisors is obtained by taking LCM of 6,7,8,9,10

LCM of divisors is 2³x3²x5x7 = 2520

now divide the greatest 6 digit number 999999 by 2520 and subtract the remainder from the largest 6 digit number

999999 divided by 2520 leaves a remainder of 2079

so subtract 2079 from 999999

which gives 997920

Now this number when divided by 6,7,8,9,10 leaves remainders of 4,5,6,7,8.

Hope this helps you.

Mark me as brainiest if the answer is correct

Answer 2

Answer:

997920 is the correct answer