find the greatest number of three digits which is a perfect square
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As we know,
the greatest no. of 3-digits = 999
=> We need to find such a perfect square no. which is the closest perfect square no. to 999.
________________________
Let's try it out:
i. Let's have the square of 30 ----
30^2 = 900. ( Closer to 999)
ii Square of 32 ----
32^2 = 1024 (1024 > 999; it exceeds 999 and hence, it's not the eligible answer.)
iii Square of 31 ---
31^2 = 961 (Closest to 999)
Therefore, the required answer would be 961 which is the greatest 3-digit perfect square number.
________________________
Hope it helps! ^_^ Please do mark it as the brainliest! ✌
the greatest no. of 3-digits = 999
=> We need to find such a perfect square no. which is the closest perfect square no. to 999.
________________________
Let's try it out:
i. Let's have the square of 30 ----
30^2 = 900. ( Closer to 999)
ii Square of 32 ----
32^2 = 1024 (1024 > 999; it exceeds 999 and hence, it's not the eligible answer.)
iii Square of 31 ---
31^2 = 961 (Closest to 999)
Therefore, the required answer would be 961 which is the greatest 3-digit perfect square number.
________________________
Hope it helps! ^_^ Please do mark it as the brainliest! ✌
Answered by
1
Answer:
hey! friends ❤️
here is ur answer ❤️
Greatest 3 - digit number = 999
Finding the square root of 999 , v see that ( 31 )^2 is less than 999 by 38.
• Required perfect square = 999 - 38 = 9
√961 = 31
(^ means=> square root)
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