Question

find the greatest number of two digit which is a perfect square

Answer 1

${9}^{2} = 81$
81 is the perfect square number

Answer 2

The answer is given below :

The answer can be found easily by finding the square values as followed -

${1}^{2} = 1 \\ \\ {2}^{2} = 4 \\ \\ {3}^{2} = 9 \\ \\ {4}^{2} = 16 \\ \\ {5}^{2} = 25 \\ \\ {6}^{2} = 36 \\ \\ {7}^{2} = 49 \\ \\ {8}^{2} = 64 \\ \\ {9}^{2} = 81 \\ \\ {10}^{2} = 100$

So, it can be concluded easily that 81 is the required perfect square in two digits.

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