Question

find the greatest number of5 digit exactly divisible by 2 ,4,6,8,10 ​

Answer 1

Answer:

99,960

Step-by-step explanation:

lcm of 2,4,6,8,10 = 120

the biggest no. of 5 digit = 99999

99999÷120, reminder=39

99999-39=99,960 ans.....

Answer 2

Answer:

Step-by-step explanation:

First take L.C.M of the no. 2,4,6,8,10.

2 = 1×2

4= 1× 2^2

6 = 1×2×3

8=1×2^3

10= 1×2×5

We get L.C.M =8×3×5=120.

Greatest 5 digit no. = 99999

Divide the no. By 120

99999÷120

We will get remainder 39

Now subtract 39 from 99999.

Resultant will be the required number

99999 - 39 = 99960

So, 99960 is the required number.

Hope it helps. Thanks