Question

Find the greatest number that can divide 3260 and 1471 leaving remainder 2 and 5 respectively

Answer 1

${ \boxed{ \boxed{ \bold \red{3260-2=3258}}}}$

${ \boxed{ \boxed{ \bold \red{1471-5=1466}}}}$

$\small{ \boxed{ \boxed{ \bold \red{then \: take \: HCF \: of \: 3258 \: and \: 1466}}}}$

$\small{ \boxed{ \boxed{ \bold \red{so \: the \: answer \: is \: 2 }}}}$

Answer 2

Answer:

it is not possible for any number

Step-by-step explanation:

here to find number we need to find HCF of (3260-2) and (1471 -5)

that is hcf of 3258 and 1466 which is 2

but when we divide 3260 by 2 we get remainder 0 instead of 2 and when we divide 1471 by 2 we get remainder 1 instead of 5.

therefore no number can divide 3260 and 1471 to give remainder 2 and 5 respectively